WebJun 9, 2011 · This has been tested on an 2M element list with 4 unique values, and the size of the list/array and number of unique elements will have an impact. Other solutions using numpy on an array can be found in Get a list of all indices of repeated elements in a numpy array; Tested in [python 3.10.4, numpy 1.23.1] and [python 3.11.0, numpy 1.23.4] WebJun 26, 2024 · All you need to do is to convert the index found by np.argmax () into your matrix indexes. This answer shows how to do that. This is how you could do it. import numpy as np a = np.array ( [ [1, 2, 3], [3, 4, 7], [4, 5, 1]]) max_index = np.argmax (a) tuple_result = (max_index // a.shape [0], max_index % a.shape [1]) print (tuple_result) Share
How to find the Index of value in Numpy Array
WebApr 25, 2024 · What *exactly* is electrical current, voltage, and resistance? Suing a Police Officer Instead of the Police Department How to open locks... WebIn below examples we use python like slicing to get values at indices in numpy arrays. First we fetch value at index 2 in a 1D array then we fetch value at index (1,2) of a 2D array. … how to replace siding on old house
Find the index of minimum values in given array in Python
WebJul 7, 2015 · >>> dict ( (x, indices (List, x)) for x in set (List) if List.count (x) > 1) {'A': [0, 2]} As for solving it using the index method of list instead, that method takes a second optional argument indicating where to start, so you could just repeatedly call it with the previous index plus 1. >>> List.index ("A") 0 >>> List.index ("A", 1) 2 Share WebMay 26, 2014 · for index, item in enumerate (items): print (index, item) And note that Python's indexes start at zero, so you would get 0 to 4 with the above. If you want the count, 1 to 5, do this: count = 0 # in case items is empty and you need it after the loop for count, item in enumerate (items, start=1): print (count, item) Unidiomatic control flow WebYou can use np.where to return a tuple of arrays of x and y indices where a given condition holds in an array. If a is the name of your array: >>> np.where (a == 1) (array ( [0, 0, 1, 1]), array ( [0, 1, 2, 3])) If you want a list of (x, y) pairs, you could zip the two arrays: >>> list (zip (*np.where (a == 1))) [ (0, 0), (0, 1), (1, 2), (1, 3)] how to replace signature in adobe pro